IPv4 Subnet Calculating

Calculating the Netmask Length (also called a prefix):

https://networkengineering.stackexchange.com/questions/7106/how-do-you-calculate-the-prefix-network-subnet-and-host-numbers

Convert the dotted-decimal representation of the netmask to binary. Then, count the number of contiguous 1 bits, starting at the most significant bit in the first octet (i.e. the left-hand-side of the binary number).

255.255.248.0   in binary: 11111111 11111111 11111000 00000000
                           -----------------------------------
                           I counted twenty-one 1s             -------> /21

The prefix of 128.42.5.4 with a 255.255.248.0 netmask is /21.

Calculating the Network Address:

The network address is the logical AND of the respective bits in the binary representation of the IP address and network mask. Align the bits in both addresses, and perform a logical AND on each pair of the respective bits. Then convert the individual octets of the result back to decimal.

Logical AND truth table:

Logical AND
128.42.5.4      in binary: 10000000 00101010 00000101 00000100
255.255.248. 0   in binary: 11111111 11111111 11111000 00000000
                           ----------------------------------- [Logical AND]
                           10000000 00101010 00000000 00000000 ------> 128.42.0.0

As you can see, the network address of 128.42.5.4/21 is 128.42.0.0

Calculating the Broadcast Address:

The broadcast address converts all host bits to 1s…

Remember that our IP address in decimal is:

128.42.5.4      in binary: 10000000 00101010 00000101 00000100

The network mask is:

255.255.248.0   in binary: 11111111 11111111 11111000 00000000

This means our host bits are the last 11 bits of the IP address, because we find the host mask by inverting the network mask:

Host bit mask            : 00000000 00000000 00000hhh hhhhhhhh

To calculate the broadcast address, we force all host bits to be 1s:

128.42.5.4      in binary: 10000000 00101010 00000101 00000100
Host bit mask            : 00000000 00000000 00000hhh hhhhhhhh
                           ----------------------------------- [Force host bits]
                           10000000 00101010 00000111 11111111 ----> 128.42.7.255

Calculating subnets:

You haven’t given enough information to calculate subnets for this network; as a general rule you build subnets by reallocating some of the host bits as network bits for each subnet. Many times there isn’t one right way to subnet a block… depending on your constraints, there could be several valid ways to subnet a block of addresses.

Let’s assume we will break 128.42.0.0/21 into 4 subnets that must hold at least 100 hosts each…

subnetting

In this example, we know that you need at least a /25 prefix to contain 100 hosts; I chose a /24 because it falls on an octet boundary. Notice that the network address for each subnet borrows host bits from the parent network block.

Finding the required subnet masklength or netmask:

How did I know that I need at least a /25 masklength for 100 hosts? Calculate the prefix by backing into the number of host bits required to contain 100 hosts. One needs 7 host bits to contain 100 hosts. Officially this is calculated with:

Host bits = Log2(Number-of-hosts) = Log2(100) = 6.643

Since IPv4 addresses are 32 bits wide, and we are using the host bits (i.e. least significant bits), simply subtract 7 from 32 to calculate the minimum subnet prefix for each subnet… 32 – 7 = 25.

The lazy way to break 128.42.0.0/21 into four equal subnets:

Since we only want four subnets from the whole 128.42.0.0/21 block, we could use /23 subnets. I chose /23 because we need 4 subnets… i.e. an extra two bits added to the netmask.

This is an equally-valid answer to the constraint, using /23 subnets of 128.42.0.0/21…

subnetting, 2nd option

Calculating the host number:

This is what we’ve already done above… just reuse the host mask from the work we did when we calculated the broadcast address of 128.42.5.4/21… This time I’ll use 1s instead of h, because we need to perform a logical AND on the network address again.

128.42.5.4      in binary: 10000000 00101010 00000101 00000100
Host bit mask            : 00000000 00000000 00000111 11111111
                           ----------------------------------- [Logical AND]
                           00000000 00000000 00000101 00000100 -----> 0.0.5.4

Calculating the maximum possible number of hosts in a subnet:

To find the maximum number of hosts, look at the number of binary bits in the host number above. The easiest way to do this is to subtract the netmask length from 32 (number of bits in an IPv4 address). This gives you the number of host bits in the address. At that point…

Maximum Number of hosts = 2**(32 – netmask_length) – 2

The reason we subtract 2 above is because the all-ones and all-zeros host numbers are reserved. The all-zeros host number is the network number; the all-ones host number is the broadcast address.

Using the example subnet of 128.42.0.0/21 above, the number of hosts is…

Maximum Number of hosts = 2**(32 – 21) – 2 = 2048 – 2 = 2046

Finding the maximum netmask (minimum hostmask) which contains two IP addresses:

Suppose someone gives us two IP addresses and expects us to find the longest netmask which contains both of them; for example, what if we had:

  • 128.42.5.17
  • 128.42.5.67

The easiest thing to do is to convert both to binary and look for the longest string of network-bits from the left-hand side of the address.

128.42.5.17     in binary: 10000000 00101010 00000101 00010001
128.42.5.67     in binary: 10000000 00101010 00000101 01000011
                           ^                           ^     ^
                           |                           |     |
                           +--------- Network ---------+Host-+
                             (All bits are the same)    Bits

In this case the maximum netmask (minimum hostmask) would be /25

NOTE: If you try starting from the right-hand side, don’t get tricked just because you find one matching column of bits; there could be unmatched bits beyond those matching bits. Honestly, the safest thing to do is to start from the left-hand side.

Powershell : Useful Commands

Get members of a group:

get-adgroupmember -identity <GROUPNAME>

Get a list of user’s “PasswordLastSet” field has a date greater than 31/01/2000 along with their usernames and email addresses:

get-aduser -filter * -Properties PasswordLastSet | where {$_.passwordLastSet -ge [DateTime] "01/31/2000 00:01 AM"} | Select-Object Name, PasswordLastSet, SamAccountName, EmailAddress

Compare two CSV files for differences:

$refCSV = import-csv .\Source.csv 
$compCSV = import-csv .\Reference.csv 
compare-object -referenceobject $refCSV -DifferenceObject $compCSV | foreach { $_.InputObject}

Iterate over a text file of usernames (one per line) and query AD for some values, printing the useraccount’s containing OU in a easily readable form and output to results.csv:

$usersaffected = "c:\tmp\listofusernames.txt"
$output = foreach ($line in get-content $usersaffected) {get-aduser $line -Properties * | Select @{l='OU';e={$_.DistinguishedName.split(',')[1].split('=')[1]}},"whenCreated", "emailaddress", "passwordLastSet", "distinguishedName"}
$output | export-csv -path c:\tmp\results.csv

Create El Capitan 10.11 USB Installer Disk

  1. Download the installer from the App Store but do not install it, close the installer when it launches
  2. Format an 8GB+ USB Drive in the GUID type and Journaled (not case sensitive) partition
  3. run the command (where Untitled is the name of the partition you created in step 1):
    sudo /Applications/Install\ OS\ X\ El\ Capitan.app/Contents/Resources/createinstallmedia --volume /Volumes/Untitled --applicationpath /Applications/Install\ OS\ X\ El\ Capitan.app --nointeraction
  4. Sit back and relax, smoke a pipe while you wait maybe

django setup with virtualenv & PyCharm

Setting up my django development (basic).

The following steps assuming that Python is installed.

  1. Setup a repository on Bitbucket:
    Ensure my development machine has access via SSH keys
  2. Install pip on development machine:
    https://pip.pypa.io/en/stable/installing.html:
    To install pip, securely download get-pip.py
    Then run the following (which may require administrator access):

    $[sudo] python get-pip.py
  3. Install virtualenv on the development machine:
    https://virtualenv.pypa.io/en/latest/installation.html

    $ [sudo] pip install virtualenv
  4. Create a working directory for the project:
    $mkdir /path/to/project/root
  5. Create the virtual environment to work from:
    $virtualenv /path/to/project/root/env
  6. Activate the virtual environment:
    $source /path/to/project/root/env/bin/activate
  7. Install mysql-python:
    (env)$[sudo]apt-get install python-dev libmysqlclient-dev
    
    (env)$pip install MySQL-python
  8. Install django 1.7:
    (env)$pip install django==1.7

    exit the virtualenv for now by:

    (env)$ deactivate
  9. Install pycharm to manage the project from a GUI:
    First install java:

    $ sudo add-apt-repository ppa:webupd8team/java
    $ sudo apt-get update
    $ sudo apt-get install oracle-java8-installer
    $ sudo apt-get install oracle-java8-set-default

    Next install pycharm:

    Download from https://www.jetbrains.com/pycharm/download/
    or from a directory outside of your project directory:

    $ wget http://download.jetbrains.com/python/pycharm-community-4.5.3.tar.gz

    change to that directory and :

    $ tar -xvf pycharm-community-4.5.3.tar.gz

    now to launch pycharm:

    $ ./pycharm-community-4.5.3/bin/pycharm.sh

 

Django 1.7, mysql-python and the pycharm editor should now be ready to use!

 

Next: Setting up the itstock django project http://www.davegernon.co.uk/techblog/initial-django-setup-for-itstock-project/